Key Idea: Add a geometric sequence forever and the total can settle to a finite number. It shows up on both papers, and the whole topic hinges on one convergence check.
♾️ The sum to infinity
- the first term
- the common ratio (next ÷ current)
S∞ exists only when |r| < 1, because the terms shrink toward 0. If |r| ≥ 1 the terms don't shrink, the total grows without limit, and there is no sum to infinity — give a finite sum instead. State |r| < 1 before you compute.
🔁 The exam variations
✏️ IB-style worked examples
IB-style question — find the sum to infinity
Find the sum to infinity of 18 + 6 + 2 + … .
Step by step:
Find r by dividing consecutive terms, and check it converges.
Substitute u₁ = 18 and r = ⅓ into the formula.
Finish.
S∞ = 27.
IB-style question — given S∞, find the first term
A geometric series has common ratio r = 0.4 and a sum to infinity of 45. Find the first term.
Step by step:
Write the formula and substitute what you know.
Work out the denominator (1 − r).
Multiply both sides by 0.6 to isolate u₁.
u₁ = 27.
IB-style question — total distance of a bouncing ball
A ball is dropped from 12 m and rebounds to ½ of its height each bounce, forever. Find the total distance it travels.
Step by step:
It drops 12 m once; then each rebound is travelled up and back down. The rebound heights 6, 3, 1.5, … are geometric (u₁ = 6, r = ½) — sum them to infinity.
Total = the drop, plus twice the rebound sum.
36 m. (Shortcut: total = x(1 + r)/(1 − r); with r = ⅔ that's the classic δ = 5x.)
Important: S∞ = u₁/(1 − r) only works when |r| < 1. If |r| ≥ 1 there is no sum to infinity — the question wants a finite sum Sₙ (often the first 2m terms). Always check |r| before reaching for S∞.
Tap each card to reveal the answer.
Exam Tips
- S∞ exists ONLY when |r| < 1; then S∞ = u₁/(1 − r). State the check first.
- Find r as next ÷ current before doing anything else.
- Given S∞, rearrange for u₁ or r — the denominator is 1 − r, never r.
- Partial sums approach S∞: the gap is u₁rⁿ/(1 − r); set it below the tolerance and round up.
- If |r| ≥ 1 there is no S∞ — give a finite sum Sₙ, simplifying with r²ᵐ = (r²)ᵐ.