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NotesMath AA SLTopic 5.11Definite integrals
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5.11.11 min read

Definite integrals

IB Mathematics: Analysis and Approaches • Unit 5

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Contents

  • Properties of definite integrals
  • Trig & exponential definite integrals
  • Rate of change → total change
Zero width, swapping limits, and splitting: Useful facts: ∫ₐᵃ f = 0 (zero-width); ∫ₐᵇ f = −∫_b^a f (swapping limits flips the sign); and ∫ₐᵇ f + ∫_b^c f = ∫ₐ^c f (you can split or join an interval). Constants and sums also pull through.

IB-style question — use the split property

Given ∫₀³ f(x) dx = 7 and ∫₀⁵ f(x) dx = 12, find ∫₃⁵ f(x) dx.

Step by step

  1. Use ∫₀³ + ∫₃⁵ = ∫₀⁵.
  2. Subtract.

Final answer

∫₃⁵ f(x) dx = 5.

Split at a shared limit: When two integrals share a limit, you can add or subtract them to get the piece you need.
Antiderivative, then F(b) − F(a): Integrate the trig/exponential, then substitute the limits. Use ∫cos x dx = sin x, ∫sin x dx = −cos x, ∫eˣ dx = eˣ (and the linear-inside ÷ a versions).

IB-style question — trig & exp

Evaluate ∫₀π/2 cos x dx and ∫₀¹ e2x dx.

Step by step

  1. First integral.
  2. Second (∫e2x = ½e2x).

Final answer

∫₀π/2 cos x dx = 1; ∫₀¹ e2x dx = ½(e² − 1) ≈ 3.19.

Radians for trig limits: Trig integrals use radian limits (e.g. π/2). Keep your GDC in radian mode for these.

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Integrate a rate to get the accumulated change: If you know a rate of change, the definite integral of the rate gives the total change: the amount at time b is (amount at a) + ∫ₐᵇ (rate) dt. On Paper 2 use the GDC's numerical integral.

IB-style question — accumulated change

A population changes at rate dP/dt = −80e−0.2t per year. If P = 2000 at t = 0, find P when t = 10.

Step by step

  1. Total change = ∫₀¹⁰ (rate) dt (GDC).
  2. Add to the starting amount.

Final answer

P(10) ≈ 1654.

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Given ∫₁⁴ f(x) dx = 10 and ∫₁⁷ f(x) dx = 26, find ∫₄⁷ f(x) dx. [2 marks]

Related Math AA SL Topics

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5.1.1Derivative as gradient
5.2.1Increasing & decreasing
5.3.1Differentiating powers
5.3.2Gradient at a point
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