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Topic 5.8Math AA SL SL27 flashcards

Optimisation & inflexion

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Card 1 of 275.8.1
5.8.1
Question

What is a stationary point?

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All Flashcards in Topic 5.8

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5.8.19 cards

Card 1definition
Question

What is a stationary point?

Answer

A point where the gradient is zero: f'(x) = 0.

Card 2concept
Question

How do you find stationary points?

Answer

Differentiate and solve f'(x) = 0.

Card 3concept
Question

How do you classify a stationary point with the second derivative?

Answer

f''(x) > 0 → minimum, f''(x) < 0 → maximum.

Card 4concept
Question

What if f''(x) = 0 at a stationary point?

Answer

The test is inconclusive; check the sign of f'(x) on each side.

Card 5concept
Question

How do you find the y-coordinate of a stationary point?

Answer

Substitute the x-value into the original function f(x).

Card 6concept
Question

How many stationary points does a cubic usually have?

Answer

Two — a local maximum and a local minimum (or none).

Card 7concept
Question

What does the first-derivative (sign) test do?

Answer

Checks the sign of f' just before and after: +→− max, −→+ min.

Card 8concept
Question

Stationary points of x³ − 6x² + 9x?

Answer

x = 1 and x = 3 (from 3(x−1)(x−3) = 0).

Card 9concept
Question

Is a stationary point always a max or min?

Answer

No — it could be a (stationary) point of inflexion.

5.8.29 cards

Card 10concept
Question

What are the steps of an optimisation problem?

Answer

Model the quantity → use the constraint to get one variable → differentiate → solve f'(x)=0 → classify → answer.

Card 11concept
Question

Why must the quantity be in one variable?

Answer

You can only differentiate a function of a single variable.

Card 12concept
Question

How do you eliminate the second variable?

Answer

Use the given constraint (fixed perimeter, total length, etc.) to substitute.

Card 13concept
Question

How do you find the optimal value?

Answer

Solve f'(x) = 0.

Card 14concept
Question

How do you confirm a maximum?

Answer

Show f''(x) < 0 (or that f' changes + to −) at that x.

Card 15concept
Question

What form do many cost problems take?

Answer

A reciprocal model like T = ax + b/x.

Card 16concept
Question

How do you differentiate b/x?

Answer

Write it as bx⁻¹; its derivative is −bx⁻² = −b/x².

Card 17concept
Question

Why keep only positive solutions?

Answer

Lengths, volumes and similar physical quantities can't be negative.

Card 18concept
Question

What should the final answer give?

Answer

Whatever the question asks — dimensions and/or the maximum/minimum value.

5.8.39 cards

Card 19definition
Question

What is a point of inflexion?

Answer

A point where the curve changes concavity (concave up ↔ concave down).

Card 20concept
Question

What two conditions define a point of inflexion?

Answer

f''(x) = 0 AND f'' changes sign through that point.

Card 21concept
Question

How do you find a point of inflexion?

Answer

Solve f''(x) = 0, confirm f'' changes sign, then find y from f(x).

Card 22concept
Question

Is f''(x) = 0 enough for an inflexion?

Answer

No — f'' must also change sign; e.g. y = x⁴ at x = 0 is not an inflexion.

Card 23concept
Question

How do you confirm the sign change?

Answer

Test f'' at a value just below and just above the candidate x.

Card 24concept
Question

Where do you get the y-coordinate?

Answer

From the original function f(x).

Card 25concept
Question

Point of inflexion of y = x³?

Answer

(0, 0).

Card 26concept
Question

Why is y = x⁴ not inflexion at 0?

Answer

f''(x) = 12x² ≥ 0 on both sides — no sign change.

Card 27concept
Question

Concavity each side of an inflexion?

Answer

Opposite: one side concave up, the other concave down.

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IB Math AA SL SL Topic 5.8 Flashcards | Optimisation & inflexion | Aimnova | Aimnova