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Topic 5.4Math AA SL SL18 flashcards

Tangents & normals

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Card 1 of 185.4.1
5.4.1
Question

What is the gradient of the tangent at x = a?

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All Flashcards in Topic 5.4

Below are all 18 flashcards for this topic. Sign up free to track your progress and get personalized review schedules.

5.4.19 cards

Card 1concept
Question

What is the gradient of the tangent at x = a?

Answer

f'(a) — the derivative evaluated at a.

Card 2concept
Question

What point does the tangent at x = a pass through?

Answer

(a, f(a)) — the point of contact on the curve.

Card 3formula
Question

What form do you use for a tangent equation?

Answer

y − y₁ = m(x − x₁), with m = f'(a) and (x₁, y₁) = (a, f(a)).

Card 4concept
Question

Where do you get the y-coordinate of the point of contact?

Answer

Substitute x = a into the original f(x), not into f'(x).

Card 5concept
Question

What is the gradient of a horizontal tangent?

Answer

0.

Card 6concept
Question

How do you find horizontal tangents?

Answer

Solve f'(x) = 0, then find the y-values.

Card 7concept
Question

What form does a horizontal tangent take?

Answer

y = a constant (the y-coordinate of the point).

Card 8concept
Question

What gradient does a tangent parallel to y = mx + c have?

Answer

The same gradient m as the line.

Card 9concept
Question

Steps to find a tangent equation?

Answer

Differentiate → f'(a) for gradient; f(a) for the point; substitute into y − y₁ = m(x − x₁).

5.4.29 cards

Card 10definition
Question

What is the normal to a curve at a point?

Answer

The line through the point that is perpendicular to the tangent there.

Card 11formula
Question

What is the gradient of the normal?

Answer

−1/f'(a) — the negative reciprocal of the tangent's gradient.

Card 12concept
Question

How do you get the normal gradient from the tangent gradient?

Answer

Flip it and change the sign (negative reciprocal).

Card 13concept
Question

What point does the normal pass through?

Answer

The same point of contact (a, f(a)) as the tangent.

Card 14concept
Question

Tangent gradient 2 → normal gradient?

Answer

−1/2.

Card 15concept
Question

Tangent gradient −3 → normal gradient?

Answer

+1/3.

Card 16concept
Question

What is the normal at a stationary point?

Answer

A vertical line x = a (since the tangent is horizontal).

Card 17concept
Question

Why can't you use −1/f'(a) at a stationary point?

Answer

f'(a) = 0, so −1/0 is undefined; geometrically the normal is vertical.

Card 18concept
Question

Method to find a normal equation?

Answer

Find f'(a), take −1/f'(a), find the point (a, f(a)), then y − y₁ = m(x − x₁).

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