Back to Topic 3.8 — Trig equations
3.8.1Math AA SL SL9 flashcards

Solving trig equations

Practice Flashcards

Flip to reveal answers
Card 1 of 93.8.1
3.8.1
Question

Why do trig equations have several solutions?

Click to reveal answer

Track your progress — Sign up free to save your progress and get smart review reminders based on spaced repetition.

All 9 Flashcards — Solving trig equations

Sign up free to track progress and get spaced-repetition review schedules.

Card 1concept

Question

Why do trig equations have several solutions?

Answer

sin, cos and tan are periodic, so they hit the same value repeatedly.

Card 2concept

Question

After the first solution, how do you get the others for sin x = k?

Answer

Use x and 180° − x (then add periods if needed).

Card 3concept

Question

Second solution pattern for cos x = k?

Answer

x and 360° − x.

Card 4concept

Question

Second solution pattern for tan x = k?

Answer

x and x + 180°.

Card 5concept

Question

How do you solve sin(2x) = k over an interval?

Answer

Solve for 2x over the doubled interval, find all solutions, then divide each by 2.

Card 6concept

Question

How many solutions does sin(2x) = k give on 0°–360°?

Answer

Up to four (the doubled interval 0°–720° gives twice as many).

Card 7concept

Question

How do you solve 2sin²x − sin x − 1 = 0?

Answer

Let s = sin x, factor (2s+1)(s−1)=0, then solve sin x = each value.

Card 8concept

Question

What if the equation mixes sin² and cos?

Answer

Use cos²x = 1 − sin²x (or vice versa) to get one ratio, then it's a quadratic.

Card 9concept

Question

Paper 2 method for trig equations?

Answer

Graph each side and use intersect (or graph the difference and find zeros) over the interval.

Track your progress with spaced repetition

Sign up free — Aimnova tells you exactly which cards to review and when, so you remember everything before your IB exam.

Start Free