Back to Topic 1.9 — Binomial theorem
1.9.3Math AA SL SL10 flashcards

Finding a term

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Card 1 of 101.9.3
1.9.3
Question

In (3x − 2)⁵ a student writes the x² term as ⁵C₃ x² · 2³. What is wrong?

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All 10 Flashcards — Finding a term

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Card 1concept

Question

In (3x − 2)⁵ a student writes the x² term as ⁵C₃ x² · 2³. What is wrong?

Answer

Two errors — the sign and the 3. Here a = 3x (not x) and b = −2 (not 2). Correct: ⁵C₃ (3x)²(−2)³ = 10 × 9 × (−8) x² = −720x². Always raise the WHOLE bracket term — number, variable and sign — to its power. (General term: ⁿCᵣaⁿ⁻ʳbʳ.)

Card 2concept

Question

How do you find a specific term without expanding?

Answer

Use the general term ⁿCᵣ aⁿ⁻ʳ bʳ; set the exponent of x equal to the power you want, solve for r, then compute that one term.

Card 3concept

Question

How do you find one coefficient?

Answer

Write the general term, find the r that gives that power of x, and compute the coefficient (raising the whole coefficient/sign to the power).

Card 4concept

Question

What does 'term independent of x' (constant term) mean?

Answer

The power of x is 0. Set the exponent of x to 0, solve for r, then compute that term.

Card 5concept

Question

Given a coefficient, how do you find an unknown constant?

Answer

Write that coefficient via the general term, set it equal to the given value, and solve. E.g. (x+k)⁷ coeff x⁵ = 63 → 21k² = 63 → k = ±√3.

Card 6concept

Question

Why do you sometimes get ± for the unknown?

Answer

An even power of the unknown (e.g. k²) gives two values. Check for a restriction like 'k > 0' before keeping both.

Card 7concept

Question

How do you find an unknown power n?

Answer

Use the simplest coefficient: ⁿC₂ = n(n − 1)/2 gives a quadratic in n; solve for the positive integer.

Card 8concept

Question

From the first terms of (1 + kx)ⁿ, how do you find n and k?

Answer

Use ⁿC₁k = (x coefficient) and ⁿC₂k² = (x² coefficient); eliminate k and solve for n, then k.

Card 9concept

Question

Find the coefficient of x⁴ in (2x − 3)⁶.

Answer

r = 2: ⁶C₂(2x)⁴(−3)² = 15 × 16 × 9 = 2160.

Card 10concept

Question

Two unknowns and two coefficient conditions — fastest method?

Answer

Form both equations and divide one by the other to eliminate a variable.

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